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观察以下等式:
(x+1)(x2-x+1)=x3+1
(x+3)(x2-3x+9)=x3+27
(x+6)(x2-6x+36)=x3+216

(1)按以上等式的规律,填空:(a+b)(______)=a3+b3
(2)利用多项式的乘法法则,证明(1)中的等式成立.
(3)利用(1)中的公式化简:(x+y)(x2-xy+y2)-(x-y)(x2+xy+y2
人气:152 ℃ 时间:2019-11-10 19:54:22
解答
(1)(a+b)(a2-ab+b2)=a3+b3
(2)(a+b)(a2-ab+b2
=a3-a2b+ab2+a2b-ab2+b3
=a3+b3
(3)(x+y)(x2-xy+y2)-(x-y)(x2+xy+y2
=x3+y3-(x3-y3
=2y3
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