令x=3cosθ
则y²=4(1-cos²θ)=4sin²θ
y=2sinθ
T=6sinθ+6cosθ
=6√2(√2/2sinθ+√2/2cosθ)
=6√2(sinθcosπ/4+cosθsinπ/4)
=6√2sin(θ+π/4)
sin最大=1
所以T最大值=6√2