∵sinα=
5 |
13 |
1−sin2α |
1−(
|
12 |
13 |
∵cos(α+β)=−
4 |
5 |
∴sin(α+β)=
1−cos2(α+β |
1−(−
|
3 |
5 |
∴sinβ=sin[(α+β)-α]=sin(α+β)cosα-cos(α+β)sinα
=
3 |
5 |
12 |
13 |
4 |
5 |
5 |
13 |
=
56 |
65 |
故选C.
5 |
13 |
4 |
5 |
33 |
65 |
16 |
65 |
56 |
65 |
63 |
65 |
5 |
13 |
1−sin2α |
1−(
|
12 |
13 |
4 |
5 |
1−cos2(α+β |
1−(−
|
3 |
5 |
3 |
5 |
12 |
13 |
4 |
5 |
5 |
13 |
56 |
65 |