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已知m^2-2*根号2m+n^2+2根号3n+5=0,求根号5m^2+2n^2的值
人气:347 ℃ 时间:2020-04-10 14:55:38
解答
m^2-2√2m+n^2+2√3n+5=0
(m^2-2√2m+2)+(n^2+2√3n+3)=0
(m-√2)^2 (n-√3)^2 =0
m=√2,n=√3
所以,√5m^2 +2n^2=2√5+6
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