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化简(cosx^4+sinx^4+sinx^2cosx^2)/(sinx^6+cosx^6+2sinx^2cosx^2)
人气:380 ℃ 时间:2019-12-13 16:34:47
解答
(cosx^4+sinx^4+sinx^2cosx^2)/(sinx^6+cosx^6+2sinx^2cosx^2)=[﹙cos2x﹚2+﹙sin2x﹚2+sin2xcos2x]/[﹙sin2x﹚3+﹙cos2x﹚3+2sin2xcos2x]=[﹙sin2x+cos2x﹚2-sin2xcos2x]/﹛﹙sin2x+cos2x﹚[﹙sin2x﹚2...
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