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数学
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由f(sinx)=sinnx推出f(cosx)=cosnx,求n?
人气:226 ℃ 时间:2019-11-07 06:01:23
解答
用π/2-x代换f(sinx)=sinnx中的x得
f(cosx)=sin(nπ/2-nx),
由sin(nπ/2-nx)=cosnx得,
n=4k+1,k为整数.
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