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已知x+y=10,xy=24,求x3+y3-x2y-xy2的值
人气:307 ℃ 时间:2020-04-13 06:59:35
解答
x3+y3-x2y-xy2
=(x+y)(x2-xy+y2)-xy(x+y)
=(x+y)(x2-2xy+y2)
=(x+y)(x2+2xy+y2-4xy)
=(x+y)[(x+y)2-4xy]
=10×(100-96)
=40
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