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若x-y=5,xy=14,则x3-x2y+xy2-y3=?
人气:176 ℃ 时间:2020-05-19 21:12:31
解答
x-y=5,xy=14
x²+y²=(x-y)²+2xy=5²+2×14=53
x³-x²y+xy²-y³
=x³-y³-x²y+xy²
=(x-y)(x²+xy+y²)-xy(x-y)
=(x-y)(x²+xy+y²-xy)
=(x-y)(x²+y²)
=5×53
=265
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