(x-5)/(x-6)-(x-6)/(x-5)=k/(x²-11x+30)
[(x-5)²-(x-6)²]/(x-6)(x-5)=k/(x²-11x+30)
(2x-11)/(x-6)(x-5)=k/(x-6)(x-5）
2x-11=k (x-6)(x-5)≠0
x=(k+11)/2 x≠5且x≠6
(k+11)/2≠5且(k+11)/2≠6
k≠±1