f(x)是偶函数,f(x)=f(-x),所以-2m^2+m+3>=0且为偶数,解不等式得：-1<=m<=3/2.m属于Z,所以m=-1,0,或1.若m=-1,得到f(3)=f(5),m不为-1；若m=0,-2m^2+m+3=3为奇数,m不为0；若m=1,-2m^2+m+3=2,f(3)

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