设a1=m,a2=km,a3=k^2m,a4=k^3m…an=k^(n-1)m
a3*a4*a5=k^2*k^3*k^4m^3=k^9m^3=3
a6*a7*a8=k^5*k^6*k^7m^3=k^18m^3=24
得:k^9=8;m^3=3/8
则a9*a10*a11=k^8*k^9*k^10m^3=k^27m^3
=(k^9)^3m^3
=8^3*3/8
=3*64
=192