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cos(19π/6)+tan(16π/3)=?
人气:106 ℃ 时间:2020-10-02 00:50:07
解答
所求式
=cos[(18π+π)/6]+tan[(15π+π)/3]
=cos(3π+π/6)+tan(5π+π/3)
=-cosπ/6+tanπ/3
=-√3/2+√3
=√3/2.
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