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数学
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【sin330°*tan(-13π/3)】/【cos(-19π/6)*cos690°】
人气:109 ℃ 时间:2020-10-01 21:45:28
解答
原式=sin(-30)tan(-π/3)/[cos(5π/6)cos(-30)]
=(-1/2)(-√3)/[(-√3/2)(√3/2)
=2√3/3
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