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(b^2)/(4a^2)-(c)/(a)=
1-(1)/(x+1)=
人气:267 ℃ 时间:2020-09-06 02:58:53
解答
b²/4a²-c/a=b²/4a²-4ac/4a²=(b²-4ac)/4a²
1-1/(x+1)=(x+1-1)/(x+1)=x/(x+1)
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