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若|a-1/2|+(b+1/3)²=0 1.求a、b的值 2.求代数式4a²-2ab-b²的值
人气:156 ℃ 时间:2020-02-04 13:59:54
解答
1.
|a-1/2|+(b+1/3)²=0
|a-1/2|>=0
(b+1/3)²>=0
所以
a-1/2=0,b+1/3=0
a=1/2,b=-1/3
2.
4a²-2ab-b²
=4*(1/2)^2-2*1/2*(-1/3)-(1/3)^2
=1+1/3-1/9
=11/9
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