解: (1).f(x)=sinx+(1-cosx)/2-(1+cosx)/2+a.
=sinx+cosx+a.
∴fx)=√2sin(x-π/4)+a.
当sin(x-π/4)=-1时,f(x)min=√2.
√2*(-1)+a=√2.
∴a=2√2.
(2).∵ sinx的x∈(2kπ-π/2,2kπ,+ρ/2)为增函数, x∈(2kπ+π/2,2kπ+3π/2)为减函数.
f(x)=sin(x-π/4)+2√2的单调递增区间为:x∈(2kπ-π/4,2kπ+π/4);
f(x)的单调递减区间为:x∈(2kπ+π/4,2kπ+5π/4),k∈Z.