计算 log2(1+√2+√3)+log2(1+√2+√3)
人气:178 ℃ 时间:2020-04-20 15:58:12
解答
log2(1+根号2+根号3)+log2(1+根号2-根号3)
=log2[(1+√2+√3)(1+√2-√3)]
=log2[(1+√2)²-(√3)²]
=log2[2√2]
=log2[2^(3/2)]
=3/2
祝愉快!
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