若x^3m=4,y^3n=5,求（x^2m)^3+(y^n)^3—x^2m·y^n·x^4m·y^2n的值_数学解答

若x^3m=4,y^3n=5,求（x^2m)^3+(y^n)^3—x^2m·y^n·x^4m·y^2n的值

人气：420 ℃　时间：2020-03-23 03:11:08

解答

(x^2m)^3+(y^n)^3-x^2m*y^n*x^4m*y^2n
=x^6m+y^3n-x^6my^3n
=(x^3m)^2+y^3n-(x^3m)^2*y^3n
=4^2+5-4^2*5
=-59