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(3x²-xy)/ (9x²-6xy+y²),其中x=1/2,y=-2/3.
人气:394 ℃ 时间:2020-06-22 01:45:09
解答
(3x²-xy)/ (9x²-6xy+y²)
=x(3x-y)/(3x-y)²
=x/(3x-y)
=(1/2)/[3*1/2-(-2/3)]
=(1/2)/[3/2+2/3]
=(1/2)/(13/6)
=1/2*6/13
=3/13
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