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数学
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若sin(a+β)=1/2,cos(a-β)=1/3,则tana/tanβ=?
人气:141 ℃ 时间:2019-11-10 12:01:53
解答
sin(a+β)=sina*cosb+cosa*sinb=1/2
sin(a-β)=sina*cosb-cosa*sinb=1/3
所以sina*cosb=5/12 cosa*sinb=1/12
tana/tanβ=(sina*cosb)/ (cosa*sinb)=5
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