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求证:tan(x-π/4)=(sinx-cosx)/(sinx+cosx)
人气:121 ℃ 时间:2020-02-03 16:43:20
解答
原式=sin(x-π/4)/cos(x-π/4)=(sinxcosπ/4-cosxsinπ/4)/(cosxcosπ/4+sinxsinπ/4)=【√2/2(sinx-cosx)】/【√2/2(sinx+cosx)】=(sinx-cosx)/(sinx+cosx)=右式
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