f(x)=sin(wx-π/3) 的最小正周期为π（w>0),则函数f(x)的单调递增区间为
人气：192 ℃ 时间：2019-08-20 17:03:59
解答
最小正周期为π
则,2π/w=πw=2
f(x)=sin(2x-π/3)
单调递增区间：
kπ-π/2≤2x-π/3≤kπ+π/2
kπ/2-π/12≤x≤kπ/2+5π/12 k∈z
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