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化简再求值[(x²+y²)²-4x²y²]÷(x²-y²)
其实,x=2,y=2/3.
人气:389 ℃ 时间:2020-04-02 11:06:49
解答
原式=(x^4+2x²y²+y^4-4x²y²)/(x²-y²)=(x^4-2x²y²+y^4)/(x²-y²)=(x²-y²)²/(x²-y²)=x²-y²=4-4/9=32/9
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