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m^2(2次方)-n^2+3m-3n=0,求(m^3n-2m^2n^2=mn^3)/(2mn)+2mn的值
人气:258 ℃ 时间:2019-11-07 07:01:56
解答
m^2-n^2+3m-3n=0(m+n)(m-n)-3(m-n)=0(m-n)(m+n-3)=0m-n=0或m+n-3=0(m^3n-2m^2n^2+mn^3)/(2mn)+2mn=(m^3n-2m^2n^2+mn^3+4m^2n^2)/(2mn)=(m^3n+2m^2n^2+mn^3)/(2mn)=mn(m+n)^2/2mn=(m+n)^2/2若m-n=0,则m=n原式=2m^...
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