1 |
a+1 |
1 |
b+1 |
m=
a+b+2 |
(a+1)(b+1) |
n=
a |
a+1 |
b |
b+1 |
n=
a(b+1)+b(a+1) |
(a+1)(b+1) |
=
ab+a+b+1 |
(a+1)(b+1) |
=
a+b+2 |
(a+1)(b+1) |
∴m=n
故选C
1 |
a+1 |
1 |
b+1 |
a |
a+1 |
b |
b+1 |
1 |
a+1 |
1 |
b+1 |
a+b+2 |
(a+1)(b+1) |
a |
a+1 |
b |
b+1 |
a(b+1)+b(a+1) |
(a+1)(b+1) |
ab+a+b+1 |
(a+1)(b+1) |
a+b+2 |
(a+1)(b+1) |