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已知tanα=2,sin²α-3sinαcosα+1=
人气:177 ℃ 时间:2020-03-04 06:59:38
解答
(sinα)^2-3sinαcosα+1=[(sinα)^2-3sinαcosα+(sinα)^2+(cosα)^2]/[(sinα)^2+(cosα)^2]=[2(sinα)^2-3sinαcosα+(cosα)^2]/[(sinα)^2+(cosα)^2]分子分母同除(cosα)^2=[2(tanα)^2-3tanα+1]/[(tan...
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