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计算(x^2-y^2)÷(x分之x-y + y^2分之x^2-y^2 - x-y分之x+y)
上面一道输错了,抱歉。是这题(x^2-y^2)(x/x-y+y^2/x^2-y^2-x-y/x+y) 【/为分数线,不是除号】
人气:342 ℃ 时间:2020-07-10 10:04:06
解答
(x^2-y^2)÷(x分之x-y + y^2分之x^2-y^2 - x-y分之x+y)
=(x^2-y^2)÷(1-y +x^2/y^2-y^2 - x-x/y+y)
=(x^2-y^2)÷(1-y+y +x^2/y^2-y^2 - x-x/y)
=(x^2-y^2)÷(1+x^2/y^2-y^2 - x-x/y)
=(x^2-y^2)÷(y^2+x^2-y^4-xy^2-xy)/y^2
=(x^2-y^2)*y^2/(y^2+x^2-y^4-xy^2-xy)
=y^2(x^2-y^2)/(y^2+x^2-y^4-xy^2-xy)
漏掉了一些括号吧?对不起,输错了。已经做了,但还是感谢。
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