(x-1)²+(x+3)(x-3）+（x-3）(x-1)=(x-1)²+(x-3）[(x+3)+(x-1)]=(x-1)²+(x-3）[2x+2]=x²-2x+1+2x²+2x-6x-6=2+1+2x²-4x-6=3+2(x²-2)-6=3+4-6=1