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计算:-4(a^2n-1)^3·(b^2)^3n+3(b^3)^2n·(a^3)^2n-1
人气:378 ℃ 时间:2020-01-31 21:19:45
解答
-4(a^2n-1)^3·(b^2)^3n+3(b^3)^2n·(a^3)^2n-1
=-4(a^6n-3)·b^6n+3b^6n·(a^6n-3)
=-(a^6n-3)·b^6n
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