∵f(x)+g(x)=1/（X²-2X+1)=1/(x-1)²∴f(-x)+g(-x)=1/(-x-1)²=1/(x+1)²∴f(x)+f(-x)+g(x)+g(-x)=1/(x-1)²+1/(x+1)²∵f(x)是奇函数,g(x)是偶函数∴f(x)+f(-x)=0,g(x)=g(-x)∴2g(x)=1/(x...帮忙化简一下，谢谢g(x)=1/2[1/(x-1)²+1/(x+1)²]=(x²+1)/(x+1)²(x-1)²f(x)=2x/(x+1)²(x-1)²这样就行了