已知x^2-3x+1=0,求2x^3-3x^2-7x+2009
人气:486 ℃ 时间:2020-02-15 08:53:22
解答
2x^3-3x^2-7x+2009
=2x^3-6x^2+3x^2-7x+2009
=2(x^3-3x^2+x)-2x+3x^2-7x+2009
=2x(x^2-3x+1)+3x^2-9x+2009
=2x(x^2-3x+1)+3(x^2-3x+1)-3+2009
=0+0+2006=2006
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