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化简cosα*根号(1-sinα)/(1+sinα)+sinα*根号(1-cosα)/(1+cosα)
人气:131 ℃ 时间:2019-11-09 06:33:14
解答
cosα*根号[(1-sinα)/(1+sinα)]+sinα*根号[(1-cosα)/(1+cosα)]
=cosα*根号[(1-sinα)^2/(1-sin^2α)]+sinα*根号[(1-cosα)^2/(1-cos^2α)]
=cosα*(1-sinα)/cosα+sinα*(1-cosα)/sinα
=(1-sinα)+(1-cosα)
=2-sinα-cosα
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