>
数学
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已知△ABC的三边为a、b、c，且a+b=4，ab=1，c=
14
，试判定△ABC的形状．
人气：311 ℃ 时间：2019-10-10 03:14:37
解答
∵a+b=4，ab=1，
∴a
2
+b
2
=（a+b）
2
-2ab=16-2×1=14，
∵c=
14
，
∴c
2
=14，
∴a
2
+b
2
=c
2
，
∴△ABC为直角三角形．
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