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数学
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lim(x^2-2)/x+5),x→∞求极限
人气:127 ℃ 时间:2020-03-08 16:13:26
解答
(x^2-2)/(x+5)
=(x^2-25+23)/(x+5)
=(x^2-25)/(x+5)+23/(x+5)
=(x-5)+23/(x+5)
lim(x^2-2)/x+5)
=lim((x-5)+23/(x+5)),x→∞
=x
=∞
因此极限就是∞
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