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求不定积分∫e^2x * cos e^x dx
人气:294 ℃ 时间:2020-05-14 18:57:59
解答
∫e^2x * cos e^x dx = ∫e^x * cos e^x d(e^x) = ∫y*cosydy ___________________y = e^x = ∫ydsiny = y*siny - ∫sinydy = y*siny +cosy + C= e^x*sin(e^x) + cos(e^x) + C
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