x∈(-π/6,π/6)
2x∈(-π/3,π/3)
2x+π/3∈(0,2π/3)
sin(2x+π/3)∈(0,1]
2sin(2x+π/3)∈(0,2]
所以函数y=2sin(2x+π/3),x属于(-π/6,π/6)的值域为：(0,2]为什么sin2π/3=1?2x+π/3∈(0,2π/3)当2x+π/3=π/2时sin(2x+π/3)=1