3/π是π/3吧,
题目是：求y=2sin(2x+π/3）(-π/6＜x＜π/6）的值域
因为 -π/6≤x≤π/6 所以0 ≤2x+π/3≤2π/3
所以y=2sin(2x+π/3）(-π/6＜x＜π/6）的值域为[0,2]