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若sin(π/6-x)=1/3,则cos(2π/3+2x)=___________
人气:104 ℃ 时间:2020-05-09 17:43:57
解答
cos(2π/3+2x)
=cos[π-(π/3-2x)]
=-cos(π/3-2x)
=-cos2(π/6-x)
=-[1-2sin²(π/6-x)]
=-[1-2*(1/3)²]
=-(1-2/9)
=-7/9
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