|log(1/3) (3-x)|＞1
∴log(1/3) (3-x)＜-1=log(1/3) 3
∴-(x-3)＞3
x-3＜-3
x＜0
log(1/3) (3-x)＞1=log(1/3) (1/3)
∴3-x＜1/3
x＞8/3
∴x∈φ