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设0≤θ≤π/2,函数y=(1/sinθ-1)(1/cosθ-1),求函数的值域
人气:487 ℃ 时间:2020-05-05 21:13:05
解答
∵0≦θ≦π/2,∴函数的定义域是(0,π/2),∴0≦θ/2≦π/4,∴sin(θ/2)、cos(θ/2)不等.∴y=(1-sinθ)(1-cosθ)/(sinθcosθ)=[cos(θ/2)-sin(θ/2)]^2×2[sin(θ/2)]^2/[2sin(θ/2)c...
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