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已知cosa=-3/5,a属于(π/2,π),求sin2a,cos2a,tan2a.
人气:104 ℃ 时间:2020-06-17 00:59:43
解答
cosa=-3/5,a属于(π/2,π)
sina=4/5
sin2a
=2sinacosa
=2*(4/5)*(-3/5)
=-24/25
cos2a
=2cos^2a-1
=2*(-3/5)^2-1
=18/25-1
=-7/25
tan2a
=sin2a/cos2a
=(24/25)/(-7/25)
=-24/7
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