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(81x的四次方y的六次方分之(-2)的平方x)的平方的根号
人气:429 ℃ 时间:2020-06-14 06:45:14
解答
√{[(-2)^2x]^2/(81x^4y^1/6}
=√{[4x]^2/(81x^4y^1/6}
=√{[16x^2]/(81x^4y^1/6}
=√{[16]/(81x^2y^1/6}
=4/9*√[1/(x^2y^1/6)]
=4/9*/∣xy^1/12∣
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