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求∫(e∧xsiny-y)dx+(e∧xcosy-1)dy,其中L为点A(2,0)到点B(0,0)的圆周x^2+y^2=2x
人气:344 ℃ 时间:2020-04-12 09:42:31
解答
补上线段y = 0则令P = e^xsiny - y,dP/dy = e^xcosy - 1Q = e^xcosy - 1,dQ/dx = e^xcosy∫_L (e^xsiny - y) dx + (e^xcosy - 1) dy= ∫∫_D [(e^xcosy) - (e^xcosy - 1)] dxdy= ∫∫_D dxdy= 1/2 • π(1)...
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