f(x)=sin(x＋π/3)sin(x－2π)=[(1/2)sinx＋(√3/2)cosx]×[sinx]=(1/2)[sin²x＋√3sinxcosx]=(1/4)[1＋√3sin2x－cos2x]=(1/2)sin(2x－π/6)＋(1/2)①最值是±(1/2)＋(1/2),周期是π；②代入计算即可.