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数学
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如图,在四边形ABCD中,AB=1,BC=2,CD=2,AD=3,且∠ABC=90°,连接AC,试判断△ACD的形状.
人气:303 ℃ 时间:2019-08-21 01:18:26
解答
△ACD是直角三角形.理由是:
∵∠B=90°,AB=1,BC=2,
∴AC
2
=AB
2
+BC
2
=1+4=5,
∴AC=
5
,
又∵AC
2
+CD
2
=5+4=9,AD
2
=9,
∴AC
2
+CD
2
=AD
2
,
∴△ACD是直角三角形.
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