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计算,sin(π/12)-sin(5π/12)+2sin(π/8)sin(3π/8)
人气:489 ℃ 时间:2020-05-21 18:10:25
解答
sin(π/12)-sin(5π/12)+2sin(π/8)sin(3π/8)
=sin(π/12)-cos(π/12)+2sin(π/8)cos(π/8)
=√2sin(π/12-π/4)+sin(π/4)
=-√2sin(π/6)+sin(π/4)
=-√2/2+√2/2
=0
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