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3x^2+10x^10=a0+a1(x-1)+a2(x-1)^2+.+a9(x-1)^9+a10(x-1)^10 求a9.答案是100
人气:231 ℃ 时间:2020-05-26 20:55:21
解答
由题目可知:左侧:x^10的系数项是a10(说明a10=10)x^9的系数项是a9 + 10*a10*(-1)(关键理解后面一项 应该有10个a10项)理由如下:a10(x-1)^10=a10(x-1)(x-1)(x-1)(x-1)(x-1)(x-1)(x-1)(x-1)(x-1)(x-1)=a10(x^10+...
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