因式分解x^2+4x+3 a^2+7a+10 y^2-7y+12 q^2-6q+8_数学解答

因式分解x^2+4x+3 a^2+7a+10 y^2-7y+12 q^2-6q+8

人气：420 ℃　时间：2020-06-01 22:37:11

解答

x^2+4x+3
=(X+3)(x+1)
a^2+7a+10
=(a+2)(a+5)
y^2-7y+12
=(y-3)(y-4)
q^2-6q+8
=(q-2)(q-4)