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数学
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2n/(3n+1)和(2n+2)/(3n+4)比大小
人气:497 ℃ 时间:2019-10-18 17:13:35
解答
两者相减:2n/(3n+1)-(2n+2)/(3n+4)
通分后,分子相减结果为:-2<0,为负数;
而分母:(3n+1)(3n+4) >0,为正数;
分子分母异号.结果为负数.
故可知:2n/(3n+1)<(2n+2)/(3n+4).
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