√3sin2x-2sin(π/2+x)cos(π-x)=√3sin2x-2cosx·(-cosx)=√3sin2x+2cos²x=√3sin2x+2cos²x-1+1=√3sin2x+cos2x+1=2[(√3/2)sin2x+(1/2)cos2x]+1=2(sin2xcosπ/6+cos2xsinπ/6)+1=2sin(2x+π/6)+1